[thelist] XSL translation
Marcus Andersson
marcus at bristav.se
Mon Mar 1 09:06:38 CST 2004
Nick Lester wrote:
Try this one:
<xsl:template match="/data">
<xsl:apply-templates select="record"/>
</xsl:template>
<xsl:template match="record">
<record Title="{@Title}">
<xsl:for-each select="@*[name() != 'Title']">
<xsl:element name="{name()}">
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
</record>
</xsl:template>
/Marcus
> Hi
>
> I Asked this question a while back but I deleted the answer by mistake!!
>
> I have an XML doc like below
>
> <?xml version="1.0"?>
> <data>
> <record Title="Mr" Forename="Nick" Surname="Lester" />
> <record Title="Mr" Forename="Joe" Surname="Bloggs" />
> </data>
>
> I need an XSLT transformation that turns it into
>
> <data>
> <record Title="Mr">
> <Forename>Nick</Forename>
> <Surname>Lester</Surname>
> </record>
> <record Title="Mr">
> <Forename>Joe</Forename>
> <Surname>Bloggs</Surname>
> </record
> </data>
>
>
> All nodes apart from Title can may be different, that is they cant be
> hardcoded into the XSL as new nodes may be addes / removed such as
> <Address> <Telephone> etc...
>
> Thanks ever so much in advance...
>
> Nick
>
>
>
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