[thelist] regex help

[Frank]

At 06:11 PM 2003-09-02 -0700, you wrote:
So if I understand you correctly, you will always need to remove the third 
set of "s#" regardless? Piece o'cake.


mystring = 's111s222s333s444s555'
regex = (s[0-9]+){2}(s[0-9]+){1}


(Find 's' followed by any quantity of numbers.){twice}
          (s[0-9]+){2} = 's111s222'

(Find 's' followed by any quantity of numbers.){once}
         (s[0-9]+){1}

To access the first pattern (in parentheses means "remember this") use
         \1

To access the first pattern (in parentheses means "remember this") use
         \2

I don't know how this would be written in PHP (I think you are a PHP man, 
yes?). Pattern number two identifies the third set of "s and numbers". It 
is identified (called "backreferencing") as \2

Next  use PHP to replace \2 from $mystring with '' (nothing) and you will 
be left with

mystring = 's111s222s444s555'   <-(s333 is gone)

This is probably not the best way, but it's mighty expedient, and probably 
fast.

Hope this helps.


--
Frank Marion     lists at frankmarion.com      Keep the signal high.