[thelist] [XSL] Parent Node Name -- SOLVED

Howard Cheng howcheng at ix.netcom.com
Tue Apr 30 17:18:01 CDT 2002

Got it. It was <xsl:value-of select="name(parent::node())" />.

At 02:54 PM 4/30/2002 -0700, you wrote:
>This should be easy, but I can't seem to find the answer anywhere. I'm
>trying to get the name of a node's parent node.
>For example:
><xsl:value-of select="name()" /> -- gets the current node's name
><xsl:value of select="../name()" /> -- looks like it should get the parent
>node's name, but this only gets me an error. Is this correct syntax? Or
>perhaps something is wrong with the XML.

Howard Cheng
howcheng at ix.netcom.com
AIM: bennyphoebe
ICQ: 47319315

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