[thelist] Simple JavaScript question
Rick den Haan
rick.denhaan at gmail.com
Sat Jul 8 10:51:57 CDT 2006
John,
john at johnallsopp.co.uk wrote:
> <script language='JavaScript'>
> function changePrice(pOption)
> {
> // get what user selected
> ind = document.giftOpts.pOption.selectedIndex;
> val = document.giftOpts.pOption.options[ind].text;
> window.alert ('Debug: Inside javascript: changePrice');
> }
> </script>";
>
Here's how I'd change this to get the value of the selected option:
ind = document.getElementById(pOption).selectedIndex;
val = document.getElementById(pOption).options[ind].value;
> The select part goes like this:
>
> <form method='post' action='index.php4' name='giftOpts'><select
> name='abc' onChange='changePrice(abc)'>";
>
You're missing quotes around your abc in onChange='changePrice(abc)'.
Without quotes, Javascript will treat that as a variable name. If you
haven't defined a variable abc, this will end up sending "undefined" to
the function. Putting quotes around that will solve your problem;
<select name='abc' onChnage=\"changePrice('abc')\">
Note the backquotes, they're there because I see it's probably coming
from a PHP echo statement (given the "; at the end there).
Good luck,
Rick.
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