[thelist] undefined index error - PHP and MySQL

Jeffrey Barke jeffrey.barke at themechanism.com
Mon May 7 14:51:58 CDT 2007

The problem is that last_insert_id() function is table agnostic.

To do it your way, try:
mysql_query("insert statement");

mysql_query("select last_insert_id() as histID");
$result = mysql_query($query, $coacalendar);
$row = mysql_fetch_array($result, MYSQL_ASSOC);
$historyID = $row['histID'];
echo "<p>History ID is: $historyID</p>\n";


Jeffrey Barke
jeffery.barke at theMechanism.com
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Blah, blah, blah...

On May 7, 2007, at 3:32 PM, Pringle, Ron wrote:

> Using PHP 5.1 and MySQL 5.12, I am inserting a record into my  
> database and then attempting to grab the auto-incremented id. The  
> insert works fine but trying to define the last_insert_id as a var  
> is blowing up on me. My code is:
> mysql_query("select last_insert_id() as histID from tbl_history");
> $result = mysql_query($query, $coacalendar);
> $row = mysql_fetch_array($result, MYSQL_ASSOC);
> $historyID = $row['histID'];  <---- LINE 60
> echo "<p>History ID is: $historyID</p>\n";
> The errors are:
> Notice: Undefined index: histID in inc_edit_confirm.php on line 60
> Out of range value adjusted for column 'histID' at row 1
> When I run the query manually it aliases the column correctly, but  
> returns a value of 0 instead of the proper value.
> I've googled around off and on today but I'm not seeing the  
> probably obvious issues here.
> Any help would be greatly appreciated.
> Ron
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