[thelist] Re: [xsl] Testing for presence of node
Dhruvraj Singh
sdhruv at aalayance.com
Thu Jun 20 22:12:09 CDT 2002
Please ignore the syntax error in the code of the previous messg.
The following, stands corrected.
<xsl:for-each select="//category">
<xsl:if test="string-length(./*[name()=subcategory])>0">
Success
</xsl:if>
<xsl:if test="string-length(./*[name()=subcategory])=0">
Failure
</xsl:if>
</xsl:for-each>
--
Dhruv
Aalayance-Inc, Bangalore India
>
> -----BEGIN PGP SIGNED MESSAGE-----
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> I have an XML file that contains the following structure:
>
> <category>
> <subcategory>
> <article>
> </article>
> </subcategory>
> </category>
>
> In my XSLT stylesheet, I need to be able to test if the <category>
> node I'm working with contains a <subcategory> node. What's the best
> way to test for the presence of this node without actually doing
> anything with it? I was thinking <xsl:if test="something">.
>
> - -joeljkp
>
> - ---------------------------------------
> http://www.ballsome.com
>
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> GrkEiFZTOBoCy9EHV1HxOiTA
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