[thelist] Google fails to find sub-pages
Jane De'Ath
janed at oakwebdesign.com.au
Sun Feb 1 12:07:31 CST 2004
Hello List!
I wonder if anyone can shed some light on a problem that has been baffling me for weeks.
I registered a simple little HTML site with search engines for a client. It's got index.htm and maybe 10 sub pages. The URL is www.studiostitches.com.au
Google will find references only from the index page, but not from any of the other pages. Even if I use a specific site search it fails to find anything located on another page.
I have even added each separate page URL to Google, but so far, to no avail.
All the text is real text - not images.
Any suggestions would be most helpful
Regards
Jane
----- Original Message -----
From: jsWalter
To: thelist at lists.evolt.org
Sent: Saturday, January 31, 2004 2:43 PM
Subject: RE: [thelist] JS: compound ternary
> -----Original Message-----
> From: thelist-bounces at lists.evolt.org
> [mailto:thelist-bounces at lists.evolt.org]On Behalf Of Tom Dell'Aringa
> Sent: Friday, January 30, 2004 3:29 PM
> To: thelist at lists.evolt.org
> Subject: [thelist] JS: compound ternary
>
>
> Hey JS people,
>
> I'm trying to build a compound ternary statement and I keep falling
> flat on my face. I know I have something mixed up, I keep getting a
> syntax error. There's a bracket set missing or something. Here's the
> statement:
>
> var restrict = (document.getElementById) ?
> document.getElementById(oName) : (document.all) ? document.all[oName]
> : return;
Well, my simple test on this...
var y = 2;
var z = 7;
var x = (y == 1) ? 'y' : (z == 1) ? 'z-1' : 'z-2';
document.write ( x );
produced what I thought it would.
Try displaying values on this before trying to RETURN.
Walter
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