[thelist] PHP conditionally create a class method?

[Stephen Rider]

On Aug 27, 2008, at 12:05 PM, sbeam wrote:

> 'function' is evaluated at compile time. Therefore PHP is "seeing"  
> your
> definition of 'myfunction' regardless of what conditional it is in.

Okay.

> You can't do
> class test {
> 	function foo() { function bar() { ... } }
> }
> and then call test::bar()
> in PHP anyway. bar() is only known within the scope of foo()

That statement is flatly in opposition to the O'Reilly PHP book.  It  
states (page 66):

*** quote ***
You can nest function declarations, but with limited effect.  Nested  
declarations do not limit the visibility of the inner defined  
function, which may be called from anywhere in your program.
*** end quote ***

Just FYI, as your first point precludes using that method anyway.

> Instead, just use inheritance normally and define all your "missing  
> functions"
> in parentclass, redefining as needed in the extensions.
>
> class parentclass {
>   function a() { echo 'A '; }
>   function b() { echo 'B '; }
>   function c() { echo 'C '; }
>   function d() { echo 'D '; }
> }
>
> class child extends parentclass {
>   function a() { echo 'special A from kid! '; }
> }

Okay, _that_ was my main confusion.  I thought that would result in  
more "You've already defined that function" errors.  I'll give that a  
try.

if it doesn't work, I'll try create_function per Matt's suggestion.

Thanks.

Stephen

-- 
Stephen Rider
<http://striderweb.com/>