[thelist] Using php to transform xml

[Chris Price]

Thanks David

I figured there were a few ways of achieving it but getting it working by
this method is a great step forward and inspires me to make further
progress. Thanks for the help. Its greatly appreciated.

--
Chris

On 25 May 2012 19:14, David Miller <dmiller at mcc.ca> wrote:

> There's more than one way to do it, of course, but what you're looking for
> is the <xsl:attribute> element. Here's an example:
>
> <xsl:stylesheet version="1.0" xmlns:xsl="
> http://www.w3.org/1999/XSL/Transform">
>        <xsl:output method="html" version="1.0" encoding="UTF-8"
> indent="yes"/>
>        <xsl:template match="plan">
>                <h1>Planner</h1>
>                <xsl:apply-templates select="task"/>
>        </xsl:template>
>        <xsl:template match="task">
>                <div>
>                        <xsl:attribute name="class"><xsl:value-of
> select="status"/></xsl:attribute>
>                         <span class='title'><xsl:value-of
> select="title"/></span>
>                        <span class='description'><xsl:value-of
> select="description"/></span>
>                        <span class='notes'><xsl:value-of
> select="notes"/></span>
>                </div>
>         </xsl:template>
> </xsl:stylesheet>
>
> ======================================================================
> David R. Miller
> Manager, Software Development / Gestionnaire, Élaboration de logiciels
> Information Technology / Services informatiques
> MEDICAL COUNCIL OF CANADA / LE CONSEIL MÉDICAL DU CANADA
> Tel. / Tél. : (613) 521-6012 ext. / poste 2265
> Fax / Téléc. : (613) 521-9417
> Email / Courriel : dmiller at mcc.ca
> www.mcc.ca
>
> >Hi there
> >
> >I know I should probably do a proper course on xml and xslt but I just
> need
> >a really quick solution for this small job - then I can probe further.
> >
> >I have an xml file with nested tasks:
> >
> ><plan>
> ><task>
> >  <title>Walk</title>
> >  <status>prop</status>
> >  <description>Learn to walk</description>
> >  <notes>Gaining strength and balance</notes>
> ></task>
> >
> >I want to output xhtml so that each task has a container with a class
> >equivalent to its 'status', eg. <div
> >class='prop'><title/><description/><notes/></div>
> >
> >This is a snippet of my xsl file:
> >
> ><h1>Planner</h1>
> ><xsl:for-each select="plan/task">
> ><div>
> ><span><xsl:value-of select="status" /></span>
> ><span class='title'><xsl:value-of select="title" /></span>
> ><span class='description'><xsl:value-of select="description" /></span>
> ><span class='notes'><xsl:value-of select="notes" /></span>
> ></div>
> ></xsl:for-each>
> >
> >I don't want a 'status' span, I want it to be the class of the div.
> >
> >Does this make sense and is there a relatively simple solution?
> >
> >Thanks
> >
> >Chris.Price
> >@Choctaw.co.uk <http:\\choctaw.co.uk>
> >0777 629 0227
>
>
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